5m^2=1875+2m^2

Solution for 5m^2=1875+2m^2 equation:

5m^2=1875+2m^2

We move all terms to the left:

5m^2-(1875+2m^2)=0

We get rid of parentheses

5m^2-2m^2-1875=0

We add all the numbers together, and all the variables

3m^2-1875=0

a = 3; b = 0; c = -1875;
Δ = b2-4ac
Δ = 02-4·3·(-1875)
Δ = 22500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{22500}=150$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-150}{2*3}=\frac{-150}{6}
=-25
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+150}{2*3}=\frac{150}{6}
=25
$